Update more than 190 brown ring formula

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SOLVED: The brown ring test for NO2^-and NO3^-is due to the formation of complex ion with formula (a) [Fe(H2O)6]^2+ (b) [Fe(H2O)5NO]^2+ (c) [Fe(H2O)(NO)5]^2+ (d) [Fe(NO)(CN)5]^2- – #22

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The formula of brown ring complex is [Fe(H2O)5(NO)]SO4. The oxidation .. – #36

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The brown ring complex compound is formulated [Fe(H2O),(NO)]SO4. The oxidation state of iron is: (a) 1 (b) 2 (1987 – 1 Ma (c) 3 (d) 0 The equivalent weight of MnSO4 is – #48

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The brown ring complex compound is formulated as [Fe(H2O)5(NO)]SO4. Th.. – #78

The compound formed in the brown ring test has the formula [Fe( H2O)5NO.. – #79

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Correct formula of the complex formed in the brown ring test for nitrates isa)FeSo.NOb)[Fe(HO)NO]2+c)[Fe(HO)NO]d)[Fe(HO)NO]3+Correct answer is option ‘B’. Can you explain this answer? – EduRev NEET Question – #86

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$Brown Ring Test \[ \left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}_{5}\l..$ Brown Ring Test \[ \left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}_{5}\l.. – #91

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Number of chelate rings in [Fe(edta) = a Number of chelate rings in (Co (en)2(NH3)C12- = b Number of chelate rings in (Ni(dmg)2] = 0 Number of chelate rings in brown ring – #97

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CFSE value of [Fe(H_2O)_5(NO)] SO_4 (Brown ring complex) is : (a) -0.8 Δ_o+P (b) -0.4 Δ_o+P (c)… – YouTube – #108

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$The formula of brown ring complex is [Fe(H_{2}O)_{5}(NO)]SO_{4}. The oxidation state of iron is ______.$ The formula of brown ring complex is [Fe(H_{2}O)_{5}(NO)]SO_{4}. The oxidation state of iron is ______. – #112

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The brown ring test for NO(2)^(-) and NO(3)^(-) is due to the formatio – #120

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$The brown ring test for $ \mathrm{NO}_{3}{ }^{-} $is due to the formation of the complex ion w.... - YouTube$ The brown ring test for $ \mathrm{NO}_{3}{ }^{-} $is due to the formation of the complex ion w…. – YouTube – #124

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The formula of brown ring complex is [Fe(H2O)s(NO)]SO4. The oxidation .. – #128

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$Correct formula of the complex formed in the brown ring test nitrates is ______.FeSO_{4}NO[Fe(H_{2}O)_{5}NO]^{+}[Fe(H_{2}O)_{5}NO]^{2+}[Fe(H_{2}O)_{5}NO]^{3+}$ Correct formula of the complex formed in the brown ring test nitrates is ______.FeSO_{4}NO[Fe(H_{2}O)_{5}NO]^{+}[Fe(H_{2}O)_{5}NO]^{2+}[Fe(H_{2}O)_{5}NO]^{3+} – #133

SOLVED: The CFSE value of [Fe(H2O)5(NO)]SO4 (brown ring complex) is: A. -0.8 âˆ˜ B. -0.4 âˆ˜ C. -1.8 âˆ˜ D. -2.4 âˆ˜ – #134

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The brown ring test for NO_(2)^(-) and NO_(3)^(-) is due to the formation of complex ion with fo… – YouTube – #136

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